60=n^2-n

Solution for 60=n^2-n equation:

60=n^2-n

We move all terms to the left:

60-(n^2-n)=0

We get rid of parentheses

-n^2+n+60=0

We add all the numbers together, and all the variables

-1n^2+n+60=0

a = -1; b = 1; c = +60;
Δ = b2-4ac
Δ = 12-4·(-1)·60
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*-1}=\frac{-1-\sqrt{241}}{-2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*-1}=\frac{-1+\sqrt{241}}{-2}
$